tag:blogger.com,1999:blog-326167780677397310.post259111943126554774..comments2024-03-27T21:35:04.988-07:00Comments on EGO OUT: JUL 02. 2016 THE FUNCTIONAL UNDERSTANDING OF TECHNOLOGY, ROLE OF ADITIVES, APPLICATION TO LENRGeorgina Popescuhttp://www.blogger.com/profile/04628821029016016988noreply@blogger.comBlogger8125tag:blogger.com,1999:blog-326167780677397310.post-74803679294039403972016-07-04T05:19:04.806-07:002016-07-04T05:19:04.806-07:00Dear Pweet,
you are right, there still is level o...Dear Pweet,<br /><br />you are right, there still is level of intensity, or additive excess heat vs. multiplicative excess heat difference between the others and Rossi.<br />This will last but not long time some creative researchers will discover the cause. <br />peterAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-326167780677397310.post-71997540305508048992016-07-04T04:47:53.281-07:002016-07-04T04:47:53.281-07:00May have seen this, may have seen that,.. at a ver...May have seen this, may have seen that,.. at a very low level,.. etc.<br />None of that is anywhere near having replicated a lenr producing kilowatts. It's the generation of kilowatts of excess heat which has made Mr Rossi's invention unique, and it is this process which the patent is supposed to protect. So far, nobody has been able to replicate this, even with the benefit of a patent to copy. Pweethttps://www.blogger.com/profile/09197878743499245329noreply@blogger.comtag:blogger.com,1999:blog-326167780677397310.post-41282651912620707412016-07-03T11:12:21.724-07:002016-07-03T11:12:21.724-07:00As i predicted, the ERV report will remain a myste...As i predicted, the ERV report will remain a mystery. The suit will be ended when Rossi fails to produce Penon for deposition under oath.brian ahernnoreply@blogger.comtag:blogger.com,1999:blog-326167780677397310.post-23580526384524716002016-07-03T07:43:35.036-07:002016-07-03T07:43:35.036-07:00MFMP may be seeing an active LENR reaction, but at...MFMP may be seeing an active LENR reaction, but at a very low level. They have seen the production of x-rays in a smoother power distribution curve up to 1.4 MeV in a burst. The production of excess heat is to insensitive a probe to detect low level LENR activity. A better problem is the production of sub-atomic particles. If MFMP would look for muons, they would most probably see the beginning of muon emissions the the LENR reaction begins and marked by the production of x-rays. Axilhttps://www.blogger.com/profile/07190120527431077518noreply@blogger.comtag:blogger.com,1999:blog-326167780677397310.post-47649556770322740292016-07-03T01:41:27.410-07:002016-07-03T01:41:27.410-07:00It's very strange that MFMP have not been able...It's very strange that MFMP have not been able to reproduce a lenr from the Rossi patent then. And that includes IH if what they say is true, that they have not been able to substantiate the claims of Rossi.<br />This also must include the MFMP crew, who seem to possess an 'ordinary skill in the art' by the looks of what they are doing. <br />How can the patent be a valid patent on a len reactor when nobody can reproduce the len reaction? <br />Is it sufficient that the patent which describes a method for heating water from an electrical heater, for it to justify it's use as a patent to protect a LEN reactor? <br />I would have thought not. <br />What am I missing here? <br />Why is Mr Rossi so pleased about his 'marvelous' American patent?<br />Why are other people so pleased he has an American patent?<br />Pweethttps://www.blogger.com/profile/09197878743499245329noreply@blogger.comtag:blogger.com,1999:blog-326167780677397310.post-65006312887059859712016-07-02T21:31:31.057-07:002016-07-02T21:31:31.057-07:00You referred to: ". . . the know-why owned on...You referred to: ". . . the know-why owned only by Rossi who knows one additive (material or functional that is still secret for all the others."<br /><br />Are you saying that Rossi did not disclose how to replicate his devices in his patents? Where did you hear this? That would invalidate the patents. A patents has to "Enable" a PHOSITA, and it has to be the "Best Configuration."<br /><br />Did he not reveal his secrets to I.H.? That would invalidate his contract with I.H.<br /><br />The patent rules are described here:<br /><br />http://www.baylor.edu/research/vpr/files/patentlawbasics.pdf<br /><br />Quote:<br /><br />i. Enablement<br /><br />The purpose of a patent is to "teach" the invention to the public. In exchange for this teaching, the public grants the inventor the monopoly which a patent represents. In order to serve this function, the patent must be explicit and detailed enough to permit or "enable" one with ordinary skill in the art to reproduce the invention without undue experimentation. If a patent is not clear enough to permit replication of the invention, then it can be invalidated.<br /><br />ii. Best Configuration<br /><br />Related to enablement, patent law also requires that the best configuration and use of the technology be disclosed. This prevents a patent being granted to someone who might wish to "hide" an optimum design: telling the world about the overall nature of the invention, but revealing only inferior embodiments of the design so as to minimize competition. . . .<br />Jed Rothwellhttps://www.blogger.com/profile/00179077151947615762noreply@blogger.comtag:blogger.com,1999:blog-326167780677397310.post-90130982583666063172016-07-02T17:12:26.282-07:002016-07-02T17:12:26.282-07:00Part 2 of 2
Proton Longevity Pushes New Bounds
ht...Part 2 of 2<br /><br />Proton Longevity Pushes New Bounds<br />https://physics.aps.org/synopsis-for/10.1103/PhysRevD.90.072005<br /><br />One interesting paragraph in this article is revealing. “Other GUTs that incorporate supersymmetry (SUSY), a hypothetical model that assumes all particles have a partner with different spin, predict that the proton decays into a K meson and a neutrino with a lifetime of less than a few times 10^^34 years. The Super-Kamiokande collaboration has looked for signs of this decay in a 50,000-ton tank of water surrounded by detectors. If one of the many protons in the tank were to decay, the K-meson’s decay products (muons, π- mesons) would be detectable.” <br /><br />These particles are seen in Leif Holmlid’s experiments. Are proton and neutron decay occurring in vast numbers in Holmlid’s experiments? What could cause the decay rate of protons to hugely increase there? <br /><br />It might be the unified coupling constant. As the power and focus of the EMF increases, the various individual force cooping constants converge to the unified value. Then the probability of proton decay goes up in proportion. One of the perplexing characteristics of the LENR reaction is its wide range of apparent power from extremely week to very strong. A varying strength of the EMF field would supply that character to the LENR reaction.<br /><br />Another amplification seen in LENR is the speed at which nuclear decay happens. In a LENR reaction the decay rare can be so rapid that a radioactive isotope reaches stability almost instantaneously. In a weak LENR reaction, the isotope’s production of radiation is only affected slightly. This may be a result in the increase of the Weak Force cooping constant through EMF stimulation as it is amplified in varying amounts toward the Weak force unification value. <br /><br />The next step in our explanation of LENR is to understand what processes in condensed matter produces powerful and focused EMF strong enough to unified the common force coupling constant. <br /><br />After all, proton decay id a mainstay of the theories of how the universe works and follows from profound universally accepted concepts of how the cosmos fundamentally operates. If protons do decay, it’s so rare that human bodies would be unaffected, but not our understanding. The impact of that knowledge would be immense, and worth a tiny bit of instability. But that instability opens up access to the limitless power stored inside the atom through the discovery of the LENR reaction.<br /><br /><br /><br />Axilhttps://www.blogger.com/profile/07190120527431077518noreply@blogger.comtag:blogger.com,1999:blog-326167780677397310.post-75505179979137615232016-07-02T17:09:52.143-07:002016-07-02T17:09:52.143-07:00Part 1 of 2
A simplified theory of LENR
A Grand ...Part 1 of 2<br /><br />A simplified theory of LENR<br /><br />A Grand Unified Theory(GUT) is a model in particle physics in which at high energy, forces of the Standard Model which define the electromagnetic, weak, and strong interactions, are merged into one single force. This unified interaction is characterized by one larger gauge symmetry and thus several force carriers, but one unified coupling constant. A common coupling constant means that each of these forces can affect the other. If Grand Unification is realized in nature, there is the possibility of a grand unification epoch in the early universe in which the fundamental forces are not yet distinct.<br /><br />There might well exist processes in condensed matter that can amplify and concentrate EMF to a high enough level to achieve a unified force coupling constant. In such a high energy state, the electromagnetic force would affect both the weak and the strong force.<br /><br />One of the predictions of the Grand Unified Theory is the decay of the proton and the neutron. Most Grand Unified Theories predict that free protons will decay. They also predict that neutrons will decay by essentially the same process,<br /><br />To prove that the Grand Unified Theory was valid, a hunt for proton decay began in the 1980s. To complete and verified theory of the standard model of physics, much rests on the existence of proton decay, and yet to this very day, we’ve never seen a proton die. The reason may simply be that protons rarely decay, a hypothesis borne out by both experiment and theory. Experiments say the proton lifetime has to be greater than about 10^^34 years: That’s a 1 followed by 34 zeroes.<br /><br />The key phrase in that last sentence is “on average.” Because of quantum physics, the time any given proton decays is random, so a tiny fraction will decay long before that 10^^34-year lifetime. So, what you need to do is to get a whole bunch of protons together. Increasing the number of protons increases the chance that one of them will decay while you’re watching.<br /><br />The second essential step is to isolate the experiment from particles that could mimic proton decay, so any realistic proton decay experiment must be located deep underground to isolate it from random particle passers-by. That’s the strategy pursued by the currently operating Super-Kamiokande experiment in Japan, which consists of a huge tank with 50,000 tons of water in a mine. The upcoming Deep Underground Neutrino Experiment, to be located in a former gold mine in South Dakota, will consist of 40,000 tons of liquid argon.<br /><br />Because the two experiments are based on different types of atoms, they are sensitive to different ways protons might decay, which will reveal which GUT is correct … if any of the current models is right. Both Super-Kamiokande and DUNE are neutrino experiments first, but we're just as interested in the proton decay possibilities of these experiments as in the neutrino aspects.<br /><br />Axilhttps://www.blogger.com/profile/07190120527431077518noreply@blogger.com